Answered

A company is conducting sweepstakes, and ships two boxes of game pieces to a particular store. Box A has 7% of its contents being winners, while 6% of the contents of box B are winners. Box A contains 40% of the total tickets. The contents of both boxes are mixed in a drawer. a) If a ticket is selected at random from the drawer, what is the probability that it is a winner

Answer :

Answer:

Probability of winner = 0.064

Step-by-step explanation:

Given:

Probability of box A = 40% = 0.4

Probability of winning box A = 7% = 0.07

Probability of box B = 1- 40% = 0.6

Probability of winning box B = 6% = 0.06

Find:

Probability of winner

Computation:

Probability of winner = Probability of box A × Probability of winning box A + Probability of box B × Probability of winning box B

Probability of winner = [0.4][0.07] + [0.6][0.06]

Probability of winner = 0.028 + 0.036

Probability of winner = 0.064

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