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The two objects shown in the beakers below are exactly the same size (same volume). Given liquid in the beakers is water (density = 1 g/mL), what is the density of the floating object?

A. 0,5g/cm^3
B. 0,6g/cm^3
C. 1g/cm^3
D. 6g/cm^3

The two objects shown in the beakers below are exactly the same size (same volume). Given liquid in the beakers is water (density = 1 g/mL), what is the densit class=

Answer :

Answer:

b.

Explanation:

Answer:

A. 0.5 g/cm3

Explanation:

Density is calculated by dividing an object's mass by its volume. The mass of the floating object is equal to the mass of the water it displaces. The volume of the water displaced by the floating object is 6 mL. Because water has a density of 1 g/mL, the mass of 6 mL of water is 6 g. Therefore, the mass of the floating object is 6 g.

The volume of the sunken object is equal to the volume of water that it displaces, which is 12 mL or 12 cm3. Because the two objects are the same size, the volume of the floating object is also 12 cm3. With both the mass and the volume of the floating object known, its density can be calculated as shown: density=massvolume=6g12cm3=0.5gcm3

The density of the floating object can also be estimated by observing how high it floats in the water. The percentage of the object that is underwater is equal to the density of the floating object. In this case, half of the object is underwater, so its density is about 0.5 g/cm3.

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