Answer :
X= 41
-(12)/(1+5x)=-(3)/(x-10)
Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
−12⋅(x−10)=(1+5x)•-3
-12⋅(x-10)=(1+5x)•-3
Solve the equation for x.
Simplify -12• (x-10)
-12x-12•-10=(1+5x) •-3
Multiply
-12 by -10
-12x+120=(1•5x)•-3
Simplify (1+5x)•-3
Apply the distributive property.
− 12x + 120 = 1• -3 + 5x •-3
Multiply
-12x+120=1⋅-3+5x⋅-3
Multiply -3 by 1
-12x+ 120=-3+5x•-3
Multiply -3 by 5
-12x +120=-3-15x
Move all terms containing x
to the left side of the equation.
Add 15x to both sides
-12x+120+15x=-3
Add
3x+120=-3
Move all terms not containing x
to the right side of the equation.
Subtract 120 from -3
3x=-123
Divide each term by 3 and simplify
Divide each term in 3x = -123 by 3.
3x / 3 = -123 / 3
Cancel the common factor of 3.
-123/3 divid by 1
X = -123/3
Divid -123/3 = 41
So X= 41
-(12)/(1+5x)=-(3)/(x-10)
Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
−12⋅(x−10)=(1+5x)•-3
-12⋅(x-10)=(1+5x)•-3
Solve the equation for x.
Simplify -12• (x-10)
-12x-12•-10=(1+5x) •-3
Multiply
-12 by -10
-12x+120=(1•5x)•-3
Simplify (1+5x)•-3
Apply the distributive property.
− 12x + 120 = 1• -3 + 5x •-3
Multiply
-12x+120=1⋅-3+5x⋅-3
Multiply -3 by 1
-12x+ 120=-3+5x•-3
Multiply -3 by 5
-12x +120=-3-15x
Move all terms containing x
to the left side of the equation.
Add 15x to both sides
-12x+120+15x=-3
Add
3x+120=-3
Move all terms not containing x
to the right side of the equation.
Subtract 120 from -3
3x=-123
Divide each term by 3 and simplify
Divide each term in 3x = -123 by 3.
3x / 3 = -123 / 3
Cancel the common factor of 3.
-123/3 divid by 1
X = -123/3
Divid -123/3 = 41
So X= 41