Answer:
60, 61, 62
Step-by-step explanation:
Let's call our first integer n.
The other two, since they are consecutive, will be n+1, and n+2.
First number: n
Second number: n + 1
Third number: n + 2
The sum of these 3 will be:
[tex]n + (n+1) + (n+2)\\3n + 1 + 2\\3n + 3[/tex]
We know that the sum, 3n+3, is equal to 183. Let's set these two equal to each other and solve the equation.
[tex]3n+3 = 183[/tex]
Subtract 3 from both sides.
[tex]3n = 180[/tex]
Divide both sides by 3.
[tex]n = 60[/tex]
Now that we know n, we can find the values of all 3 integers.
First number, n:
n = 60
Second number, n+1:
n + 1 = 60 + 1 = 61
Third number, n + 2:
n + 2 = 60 + 2 = 62
Answer: 60, 61, 62
