Bob uses a 20 foot ladder to paint a section of his house that is 16 feet high.
-
16 ft
Ladder
20 ft
80
Ground
Select all equations that can be used to solve for 0.
sin 0
12
20
cos
12
20
12
tan 8 =
20
O sin e
16
20
cos e
16
20

Bob uses a 20 foot ladder to paint a section of his house that is 16 feet high. - 16 ft Ladder 20 ft 80 Ground Select all equations that can be used to solve fo class=

Answer :

Answer:

Option (2) and Option (4)

Step-by-step explanation:

From the picture attached,

Length of ladder AC = 20 feet

Height of the highest point of the ladder from ground AB = 16 ft

By Pythagoras theorem,

AC² = BC² + AB²

BC² = AC² - AB²

BC = [tex]\sqrt{(20)^2-(16)^2}[/tex]

     = [tex]\sqrt{400-256}[/tex]

     = [tex]\sqrt{144}[/tex]

     = 12

Now, Sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}=\frac{\text{AB}}{\text{AC}}[/tex]

                 = [tex]\frac{16}{20}[/tex]

Cosθ = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{\text{BC}}{\text{AC}}[/tex]

         = [tex]\frac{12}{20}[/tex]

tanθ = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{\text{AB}}{\text{BC}}[/tex]

        = [tex]\frac{16}{12}[/tex]

Therefore, Option (2) and Option (4) are the correct options.

${teks-lihat-gambar} eudora

The equation that should be used is option 2 and option 4.

Calculation of the equation:

Since

Length of ladder AC = 20 feet

Height of the highest point of the ladder from ground AB = 16 ft

So here we apply the Pythagoras theorem,

AC² = BC² + AB²

BC² = AC² - AB²

So,

[tex]BC = \sqrt{(20)^2 - (16)^22}\\\\ = \sqrt{400 - 256}\\\\ = \sqrt{144}[/tex]

= 12

Now

Sin θ = 16\20

Cos θ = 12\20

tan θ = 16 \12

hence, The equation that should be used is option 2 and option 4.

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