Answer :

Answer:

25. Yes, it is a function, because none of the x outputs are repeating

Sueraiuka

Step-by-step explanation:

Hey there!

25). Ans;

It is a function. [ many to one function].

26).Ans; Put all values of "x" in (2x^2+7).

a. f(x) = -2

[tex] f( - 2)= 2 \times { (- 2)}^{2} + 7[/tex]

So, f(-2)= 15

b. f(x)= -1.

[tex]f( - 1) = 2 \times ( { - 1)}^{2} + 7[/tex]

So, f(-1)= 9

c. f(x)= 0

[tex]f(0) = 2 \times ( {0)}^{2} + 7[/tex]

So, f(0)= 7

d. f(x)= 1

[tex]f(1) = 2 \times {(1)}^{2} + 7[/tex]

So, f(1)= 9

e. f(x)= 2

[tex]f(2) = 2 \times {(2)}^{2} + 7[/tex]

So, f(2)= 15

f. f(x)= 3.

[tex]f(3) = 2 \times {(3)}^{2} + 7[/tex]

So, f(3)= 25.

Hope it helps...