The height of a tennis ball tossed into the air is modeled by h(x) = 40x – 16x 2, where x is elapsed time in seconds. During what time interval will the tennis ball be at least 15 feet above the ground?

Answer :

Answer: D.

Step-by-step explanation:

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The time interval between which the ball will be 15 feet above the ground is from 0.4594 seconds to 2.04 seconds.

What is a quadratic equation?

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

The solutions of a quadratic equation can be found using the formula,

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

Given that the height of a tennis ball tossed into the air is modelled by h(x)=40x – 16x², where x is elapsed time in seconds.

Now, the time interval will the tennis ball be at least 15 feet above the ground is,

h(x) = 40x – 16x²

Substitute the height of the ball as 15 feet,

h(x) = 40x – 16x²

16x² - 40x + 15 = 0

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \dfrac{-(-40)\pm \sqrt{(-40)^2 - 4(16)(15)}}{2(16)}\\\\[/tex]

x = 2.04056, 0.4594

Therefore, the time interval between which the ball will be 15 feet above the ground is from 0.4594 seconds to 2.04 seconds.

Learn more about Solutions of a Quadratic Equation:

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