Answer :

JamonBSCE

Answer:

y = 3x + 3

Step-by-step explanation:

Rules of Perpendicularity

[tex]y = mx + b[/tex] ⊥ [tex]y=-\frac{1}{m} x + b[/tex]

1 - Find your first equation

x + 3y = 272 | 1.1 - get y by itself by first subtracting x

-x          -x

     3y = -x + 272 | 1.2 - divide both sides by 3 and you've got it simplified

[tex]y = -\frac{1}{3}x + \frac{272}{3}[/tex]

That 272 over 3 looks pretty intimidating, however, all we really care about is that slope

2 - Use the slope to find the perpendicular

[tex]y = -\frac{1}{3}x+b[/tex] ⊥ [tex]y= -\frac{1}{-\frac {1}{3}}x+ b = \frac{3*1}{1} x+b = 3x+b[/tex]

[tex]y = -\frac{1}{3}x +b[/tex] ⊥ [tex]y = 3x + b[/tex]

3 - Use the perpendicular y = mx + b to find b when it passes through said point

y = 3x + b must pass through (1, 6) or (x, y)

Plug x and y in

6 = 3(1) + b

6 = 3 + b

-3  -3

3 = b

4.) Rewrite y=mx+b form with the found b

y = 3x + 3

Hope this helps,

  - J.M.Jamon

        Pennsylvania State University

        Full-time B.S.CE. undergrad student

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