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In a particular crash test, an automobile ofmass 1249 kg collides with a wall and bouncesback off the wall. Thexcomponents of theinitial and final speeds of the automobile are16 m/s and 3.6 m/s, respectively.If the collision lasts for 0.16 s, find themagnitude of the impulse due to the collision.Answer in units of kg·m/s

Answer :

Answer:

Explanation:

Impulse = change in momentum

Initial momentum = mass x velocity = 1249 x 16 = 19984 kg m/s

Final momentum = 1249 x ( - 3.6 ) = - 4496.4 kg m/s

change in momentum

final momentum- initial momentum

=  - 4496.4 - 19984 kg m/s

= -24480.4 kg m /s .

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