Problem 9.20 A sphere of uniform density with mass 18 kg and radius 0.8 m is spinning, making one complete revolution every 0.4 s. The center of mass of the sphere has a speed of 8 m/s. (a) What is the rotational kinetic energy of the sphere

Answer :

Answer:

K = 567.91 J

Explanation:

Given that,

Mass of sphere, m = 18 kg

Radius of a sphere, r = 0.8 m

It makes one complete revolution every 0.4 s.

The speed of center of mass of the sphere is 8 m/s

We need to find the rotational kinetic energy of the sphere. It is given by the formula as follows :

[tex]K=\dfrac{1}{2}I\omega^2[/tex]

I is moment of inertia,

[tex]I=\dfrac{2}{5}mr^2\\\\I=\dfrac{2}{5}\times 18\times (0.8)^2\\\\I=4.608\ kg-m^2[/tex]

[tex]\omega[/tex] is angular speed

[tex]\omega=\dfrac{2\pi }{0.4}\\\\=15.7\ rad/s[/tex]

So,

[tex]K=\dfrac{1}{2}\times 4.608\times (15.7)^2\\\\K=567.91\ J[/tex]

So, the rotational kinetic energy of the sphere is 567.91 J.

The rotational kinetic energy of the sphere is 710.8 J.

Moment of inertia of the sphere

I = ¹/₂mr²

I = 0.5 x 18 x (0.8)²

I = 5.76 kgm²

Angular speed of the sphere

ω = 2πf

ω = 2π x (1/0.4s)

ω = 15.71 rad/s

Rotational kinetic energy

K.E = ¹/₂Iω²

K.E = 0.5 x (5.76) x (15.71)²

K.E = 710.8 J

Thus, the rotational kinetic energy of the sphere is 710.8 J.

Learn more about rotational kinetic energy here: https://brainly.com/question/25803184

Other Questions