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A dentist’s drill starts from rest. After 7.28 s of constant angular acceleration it turns at a rate of 16740 rev/min. Find the drill’s angular acceleration. Answer in units of rad/s 2 .

Answer :

Answer:

[tex]\alpha =240.79\ rad/s^2[/tex]

Explanation:

Given that,

Initial angular velocity, [tex]\omega_i=0[/tex]

Final angular velocity, [tex]\omega_f=16740\ rev/min = 1753\ rad/s[/tex]

We need to find the angular acceleration of the drill. It is given by the formula as follows :

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{1753-0}{7.28}\\\\\alpha =240.79\ rad/s^2[/tex]

So, the angular acceleration of the drill is [tex]240.79\ rad/s^2[/tex].

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