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An object increases vert its velocity from 22M/S 236M/S and five seconds. What is the acceleration of the object

Answer :

Sarah06109

Answer:

[tex]\boxed {\boxed {\sf a=42.8 \ m/s^2}}[/tex]

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

[tex]a=\frac{v-u}{t}[/tex] (v is the final velocity, u is the initial velocity, t is the time).

The velocity increased from 22 m/s to 236 m/s in 5 seconds. Therefore:

[tex]v=236 \ m/s\\u=22 \ m/s\\t= 5 \ s[/tex]

Substitute the values into the formula.

[tex]a=\frac{236 \ m/s - 22 \ m/s}{5 \ s}[/tex]

Subtract in the numerator.

  • 236 m/s-22 m/s=214 m/s

[tex]a=\frac{214 \ m/s}{5 \ s}[/tex]

Divide.

[tex]a=42.8 \ m/s^2[/tex]

The acceleration of the object is 42.8 meters per square second.

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