Answer :
The volume in liters of Hydrogen gas = 49.28 L
Further explanation
The reaction equation is the chemical formula of reagents and product substances
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products
Reaction
2 Al (s) + 6 HCl (aq) → 2 AlCl₃ (aq) + 3 H₂ (g)
mol Al :
[tex]\tt mol=\dfrac{mass}{Ar}=\dfrac{40}{27}=1.481[/tex]
mol H₂ :
[tex]\tt \dfrac{3}{2}\times 1.481=2.2[/tex]
At STP, 1 mol =22.4 L
so the volume of hydrogen :
[tex]\tt 2.2 \times 22.4=49.28~L[/tex]
When 40.0 g of Al react with excess HCl at STP, 49.8 L of H₂ are produced.
Let's consider the following balanced equation.
2 Al(s) + 6 HCl(aq) → 2 AlCl₃(aq) + 3 H₂(g)
We can calculate the liters of hydrogen obtained by the reaction of 40.0 g of Al with excess HCl considering the following relationships.
- The molar mass of Al is 26.98 g/mol.
- The molar ratio of Al to H₂ is 2:3.
- 1 mole of H₂ at STP occupies 22.4 L.
[tex]40.0 g Al \times \frac{1molAl}{26.98gAl} \times \frac{3molH_2}{2molAl} \times \frac{22.4 LH_2}{1molH_2} = 49.8 LH_2[/tex]
When 40.0 g of Al react with excess HCl at STP, 49.8 L of H₂ are produced.
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