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a basketball player's three point shooting. Assume that his shots are Bernoulli trials, and that he makes 1 in 5 of his shots.

How many three point shots must the player attempt so that the probability of his hitting at least one of them is at least 0.94

Answer :

Points make = 1/5, so Points miss = 4/5  
for Points make to be ≥ 0.94, Points miss ≤0.06 in n trials 

first set (4/5)^n = 0.06

taking logs, 

n*log(4/5) = log 0.06

n = log 0.06/log(4/5) = 12.608, to be rounded

the answer is 13

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