Answer :
Answer:
The required integers are x=3 and y= -9
Step-by-step explanation:
Let one the integers be x and y
An integer is 15 more than 2 times another: x=15+2y
product of the two integers is -27: x*y=27
[tex]x=15+2y ---eq(1)\\x*y=-27----eq(2)[/tex]
Solving both equations to find values of x and y
Putting value of x from equation 1 in equation 2
[tex](15+2y)*y=-27\\15y+2y^2=-27\\Rearranging:\\2y^2+15y-27=0[/tex]
This can be solved using quadratic formula:
[tex]$y=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]
Putting values and finding factors
[tex]$y=\frac{-(15)\pm\sqrt{(15)^2-4(2)(-27)}}{2(2)}$\\$y=\frac{-(15)\pm\sqrt{225+216}}{4}$\\$y=\frac{-(15)\pm\sqrt{441}}{4}$\\$y=\frac{-(15)\pm21}{4}$\\$y=\frac{-(15)+21}{4} \ or \ y=\frac{-(15)-21}{4}$\\$y=\frac{6}{4} \ or \ y=\frac{-36}{4}$\\$y=\frac{3}{2} \ or \ y=-9$[/tex]
Since y is integer so, we consider only y= -9
The value of x will be:
[tex]x*y=-27\\x*(-9)=-27\\x=\frac{-27}{-9} \\x=3[/tex]
So, the value of x is x=3
The required integers are x=3 and y= -9