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Determine the equilibrium constant for the following reaction at 298 K. SO3
+ H20
H2SO4 (1)
AG° = -90.5 kJ
O a. 1.37 X 10-16
O b.4.78 X 10+11
O c. 9.11 X 10-8
O d. 7.31 X 10+15

Answer :

ardni313

The equilibrium constant : K = d. 7.31 X 10¹⁵

Further explanation

Gibbs free energy is the maximum possible work given by chemical reactions at constant pressure and temperature. Gibbs free energy can be used to determine the spontaneity of a reaction

Reaction

SO₃ + H₂O ⇒ H₂SO₄ ΔG° = -90.5 kJ

Formula

[tex]\tt \Delta G^o=-RT~ln~K\\\\-90.5\times 10^3~J=-8.3145~J/mol.K\times 298~K~ln~K\\\\ln~K=36.5255\rightarrow K=e^{36.5255}=7.3\times 10^{15}[/tex]

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