100. g of ice at 0 is added to 300.0 g of water at 60C. Assuming no transfer of heat to
the surroundings, what is the temperature of the liquid water after all the ice has
melted?

Answer :

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Heat of fusion of water = 333 J/g 100 g ice x 333 J/g = 33300 J (energy to melt 100 g ice at 0 deg C) 300

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