Answer :
Answer:
Step-by-step explanation:
Lines m and l are the parallel lines and a line 'n' is a transverse intersecting these lines.
m∠2 = 50°
m∠1 + m∠2 = 180° [Linear pair of angles]
m∠1 = 180° - 50°
m∠1 = 130°
m∠3 = m∠1 = 130° [Vertically opposite angles]
m∠3 + m∠5 = 180° [Consecutive interior angles]
m∠5 = 180° - m∠3
= 180° - 130°
= 50°
m∠6 + m∠5 = 180° [Linear pair of angles]
m∠6 = 180° - 50° = 130°
From the given diagram
angle 1= 130 degrees
Angle 3 = 130 degree
Angle 5= 50 degree
Angle 6= 130 degree
Given :
the two parallel lines are cut by a transversal
Angle 1 and angle 2 are linear pair of angles
Sum of angle 1 and angle 2 is 180
[tex]<1+<2=180\\<1+50=180\\<1=180-50\\<1= 130[/tex]
Angle 1 and angle 3 are vertical opposite angles
They are equal
[tex]<1=<3\\130=<3\\<3= 130[/tex]
When two parallel lines are cut by transversal , corresponding angles are equal
<5= <2
<5=50
Alternate exterior angles are congruent
<6=<1
<6=130
angle 1= 130 degrees
Angle 3 = 130 degree
Angle 5= 50 degree
Angle 6= 130 degree
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