Answer :
what you would do is that you would use the y=mx+b linear equation
m=5
x=-1
y=-3
b=?
hence, you must solve b to have the equation
-3=(5)(-1)+b
-3=-5+b
-3+5=b
2=b
therefore the equation is
y=5x+2
for standard form you just move everything to equal 0 because there is no fraction next to the x
thus
-5x+y-2=0
m=5
x=-1
y=-3
b=?
hence, you must solve b to have the equation
-3=(5)(-1)+b
-3=-5+b
-3+5=b
2=b
therefore the equation is
y=5x+2
for standard form you just move everything to equal 0 because there is no fraction next to the x
thus
-5x+y-2=0