RichRollin676
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A corner store sells two kinds of baked goods: cakes and pies. A cake costs $5 and a pie costs $4. In one day, the store sold 10 baked goods for a total of $46.
a. Write a system of equations to represent this situation.

b. Show work, using substitution, to determine how many cakes were sold

Answer :

absor201

Answer:

a. Required system of equations is:

c+p = 10

5c+4p = 46

b. 6 cakes were sold

Step-by-step explanation:

Let p be the number of pies and c be the number of cakes.

Then according to given statement " the store sold 10 baked goods"

[tex]c+p = 10\ \ \ Eqn\ 1[/tex]

And

"A cake costs $5 and a pie costs $4"

[tex]5c+4p = 46\ \ \ \ Eqn\ 2[/tex]

Using equation 1,

[tex]c=10-p[/tex]

Putting this value of c in equation 2:

[tex]5(10-p)+4p = 46\\50-5p+4p = 46\\-p = 46-50\\-p = -4\\p = 4[/tex]

Putting p = 4 in equation 1

[tex]c+4 = 10\\c = 10-4\\c =6[/tex]

Hence,

a. Required system of equations is:

c+p = 10

5c+4p = 46

b. 6 cakes were sold

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