Answer :

Given:

The expression is

[tex]\dfrac{x-5}{3x^2-10x-25}[/tex]

To find:

The restricted value of given expression.

Solution:

We have,

[tex]\dfrac{x-5}{3x^2-10x-25}[/tex]

Equate the denominate equal to 0, to find the restricted value.

[tex]3x^2-10x-25=0[/tex]

[tex]3x^2-15x+5x-25=0[/tex]

[tex]3x(x-5)+5(x-5)=0[/tex]

[tex](x-5)(3x+5)=0[/tex]

Using zero product property, we get

[tex]x-5=0\text{ and }3x+5=0[/tex]

[tex]x=5\text{ and }x=-\dfrac{5}{3}[/tex]

Therefore, the restricted values are [tex]x=5\text{ and }x=-\dfrac{5}{3}[/tex].

Other Questions