Answer :

xero099

Answer:

The vector is [tex]\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)[/tex].

Step-by-step explanation:

We can determine the equivalent vector ([tex]\vec r[/tex]), dimensionless, by means of the following formula:

[tex]\vec r = \frac{\vec u}{\|\vec u\|} \cdot \|\vec r\|[/tex] (1)

Where:

[tex]\vec u[/tex] - Original vector, dimensionless.

[tex]\|\vec u\|[/tex] - Norm of the original vector, dimensionless.

[tex]\|\vec r\|[/tex] - Norm of the new vector, dimensionless.

The norm of the original vector is determined by the following definition:

[tex]\|\vec u\| = \sqrt{\vec u\,\bullet \,\vec u}[/tex] (2)

If we know that [tex]\vec u = (3, 2, -6)[/tex], then the norm of the original vector is:

[tex]\|\vec u\| = \sqrt{(3)\cdot (3)+(2)\cdot (2)+(-6)\cdot (-6)}[/tex]

[tex]\|\vec u\| = 7[/tex]

If we know that [tex]\|\vec r\| = 2[/tex], then the new vector is:

[tex]\vec r = \frac{2}{7}\cdot (3,2,-6)[/tex]

[tex]\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)[/tex]

The vector is [tex]\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)[/tex].

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