Answered

Which is the equation of the parabola that
opens to the right, has a focus at (3.0), and
has a directrix at x=-3?

Answer :

absor201

Answer:

The equation of the parabola will be:

  • [tex]\:y^2=12x[/tex]

Step-by-step explanation:

The vertex  (h, k)  is halfway between the directrix and focus.

Find the  x  coordinate of the vertex using the formula

x = (x-coordinate of focus + directrix)/2

 = (3-3)/2

 = 0/2

 =0

The  y -coordinate will be the same as the y-coordinate of the focus.

so the vertex will be: (0, 0)

Finding the distance from the focus to the vertex

The distance from the focus to the vertex and from the vertex to the directrix is |p|.

Subtract the  x  coordinate of the vertex from the x -coordinate of the focus to find  p .

[tex]p=3-0[/tex]

[tex]p=3[/tex]

Substitute in the known values for the variables into the equation

[tex]\left(y-k\right)^2=4p\left(x-h\right)[/tex]

[tex]\left(y-0\right)^2=4\left(3\right)\left(x-0\right)[/tex]

[tex]\:y^2=12x[/tex]

Therefore, the equation of the parabola will be:

  • [tex]\:y^2=12x[/tex]

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