O.N. of Na = +1
O.N. of O = -2
Let, O.N. of Tin = x
1*2 + x + -2*2 = 0
2+x-4 = 0
x-2 = 0
x = 2
SO OPTION C IS YOUR ANSWER......
Answer: Option (C) is the correct answer.
Explanation:
It is known that oxidation number of sodium is +1 and the oxidation number of oxygen is -2.
Let the oxidation number of tin (Sn) is x.
Therefore, calculate the oxidation number of tin in the given formula as follows.
[tex]Na_{2}SnO_{2}[/tex]
= (2 \times oxidation number of Na) + Oxidation number of Sn + (2 \times oxidation number of O)
= [tex](2 \times +1) + x + (2 \times (-2))[/tex]
So, 2 + x - 4 = 0
therefore, x = +2
Thus, we can conclude that the oxidation number of tin (Sn) in the compound [tex]Na_{2}SnO_{2}[/tex] is +2.
