Ann2020
Answered

Write equilibrium constant (KC) for the following reactions

1. N2(g) + O2(g) ⇌ 2NO(g)

2. N2(g) + 3H2(g) ⇌ 2NH3(g)

3. 2SO2(s) + O2(g) ⇌ 3SO3(g)

4. 2Fe(S) + 4H2O(g) ⇌Fe3O4(s) +4H2(g)​

Answer :

ardni313

The equilibrium constant(Kc) is equal to the concentration of the products over the concentration of the reactants, and each coefficient of the compound in an equilibrium state

Further explanation

The equilibrium constant or Kc is the value of the concentration product in the equilibrium state of the substance in the right segment divided by the product of the substance in the left section, each of which has a reaction coefficient raised

solid (s) and liquid (l) have no concentration, so these two phases are not involved in the equilibrium constant KC (given the value = 1).

The equilibrium constant based on concentration (Kc) in a reaction

pA + qB -----> mC + nD

[tex]\tt Kc=\dfrac{[C]^m[D]^n}{[A]^p[B]^q}[/tex]

1.   N2(g) + O2(g) ⇌ 2NO(g)

[tex]\tt Kc=\dfrac{[NO]^2}{[N_2][O_2]}[/tex]

2. N2(g) + 3H2(g) ⇌ 2NH3(g)

[tex]\tt Kc=\dfrac{[NH_3]^2}{[N_2][H_2]^3}[/tex]

3. 2SO2(g) + O2(g) ⇌ 3SO3(g)

[tex]\tt Kc=\dfrac{[SO_3]^3}{[SO_2]^2[O_2]}[/tex]

4. 2Fe(S) + 4H2O(g) ⇌Fe3O4(s) +4H2(g)​

[tex]\tt Kc=\dfrac{[H_2]^4}{[H_2O]^4}[/tex]

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