Answer :
Answer:
490. g H₂SO₄
General Formulas and Concepts:
Chemistry - Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
Step 1: Define
3.01 × 10²⁴ molecules H₂SO₄
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of H - 1.01 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol
Step 3: Convert
[tex]3.01 \cdot 10^{24} \ molecules \ H_2SO_4(\frac{1 \ mol \ H_2SO_4}{6.022 \cdot 10^{23} \ molecules \ H_2SO_4} )(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4} )[/tex] = 490.287 g H₂SO₄
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
490.287 g H₂SO₄ ≈ 490. g H₂SO₄