Answer:
The solution is:
[tex]6x-12-x\le \:3\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:3\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:3]\end{bmatrix}[/tex]
The graph of the solution is attached below.
Both the number line and graph is attached below.
Step-by-step explanation:
Note: you missed to add the graph options. Therefore, I am solving the inequality and adding the corresponding graph which would anyways clear your concept.
Given the inequality expression
[tex]6\:x\:-\:12\:-\:x\:\le \:3[/tex]
Group like terms
[tex]6x-x-12\le \:3[/tex]
Add similar elements: 6x-x=5x
[tex]5x-12\le \:3[/tex]
Add 12 to both sides
[tex]5x-12+12\le \:3+12[/tex]
simplify
[tex]5x\le \:15[/tex]
Divide both sides by 5
[tex]\frac{5x}{5}\le \frac{15}{5}[/tex]
simplify
[tex]x\le \:3[/tex]
Therefore, the solution is:
[tex]6x-12-x\le \:3\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:3\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:3]\end{bmatrix}[/tex]
Both the number line and graph is attached below.
