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if the cross section area of small piston of a hydraulic pressure is 40cm^2 and that of large piston is 4m^2, what load is necessary on the large piston balance 600n force on the small piston.
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Answer :

lolman981234

Answer:

0.06 N

Explanation:

Convert 40cm2 = 0.004m2

By Pascal's law:

large force / large area = small force / small area

600 / 4 = small force / 0.004

small force = 0.6 ( N )

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