Answered

You have a vinegar solution you believe to be 0.73 M. You are going to titrate 20.99 mL of it with a NaOH solution that you know to be 0.583 M. At what volume of added NaOH solution would you expect to see an end point

Answer :

Answer:

The answer is "262.83 mL"

Explanation:

The equation for the reaction is :

[tex]HA+ NaOH \longrightarrow NaA+H_2 O[/tex]

a)

Calculating the moles of HA:

[tex]=0.02099 \ LHA \times \frac{0.73 \ mol \ HA}{1 \ L HA}\\\\= 0.153227 \ mol HA[/tex]

b)

Calculating the moles of NaOH:

[tex]= 0.153227 \ mol \ HA \times \frac{1 \ mol\ NaOH}{1 \ mol \ HA}\\\\ = 0.153227\ mol \ NaOH[/tex]

c)

Calculating the volume of the NaOH:

[tex]=0.153227 \ mol \ NaOH \times \frac{1 \ L \ NaOH}{0.583 \ mol \ NaOH}\\\\= 0.262825043\ L \\\\ = 262.83 \ mL[/tex]

Other Questions