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How many five-digit positive integers that are divisible by 3 can be formed using the digits 0, 1, 2, 3, 4 and 5, without any of the digits getting repeating
a) 15 b) 96
c) 216 d) 120

I am pretty confused with this, kindly explain it in detail and get a brainliest too!

Answer :

Jocelyn567

Answer:

there are a total of 120 + 96 = 216, 5 digit numbers divisible by '3' that can be formed using the digits 0 to 5.

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