Answer :

SJ2006
Atomic mass Kr = 83.8 g/mole
Atomic mass Ar = 39.948 g/mole

So the ratio of the effusion rates = SQRT(83.8/39.948) = 1.45. Argon moves 45% faster than krypton!

Hope that helped!
maacastrobr

Answer:

Ratio=1.44

Explanation:

According to Graham's law of effusion, the ratio of effusion rates for two gases can be written as:

Ratio = [tex]\sqrt{\frac{M1}{M2} }[/tex]

Where M1 and M2 are the molar masses of the gases. In this case, M1 is the atomic mass of  Kr (83.798) and M2 is the atomic mass of Ar (39.948).

Ratio = [tex]\sqrt{\frac{83.798}{39.948} }=1.44[/tex]

Thus Ar effuses 1.44 times faster than Kr

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