Answer :
binomdist with n = 3, p = 0.82, q = 1-0.82 = 0.18
P[≥2] = P[2] + P[3] = 3c2 *0.82^2*0.18 + 0.82^3 ≈ 91%
hope it helps
P[≥2] = P[2] + P[3] = 3c2 *0.82^2*0.18 + 0.82^3 ≈ 91%
hope it helps
Lesson 8: Binomial Distribution
1. a. 91%
2. a. 5.1%
3. c. s^5-25s^4v+250s^3v^2-1250s^2v^3+3125sv^4-3125v^5
4. 55.8%