Answer:
3.88 m/s North
Explanation:
We are given that
[tex]m_1=136kg[/tex]
[tex]m_2=100 kg[/tex]
[tex]v_1=6 m/s[/tex]
[tex]v_2=1m/s[/tex]
We have to find the speed and direction of the two players
immediately after the tackle.
Using linear conservation of momentum
[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]
Substitute the values
[tex]136\times 6+100\times 1=(136+100)v[/tex]
[tex]916=236v[/tex]
[tex]v=\frac{916}{236}[/tex]
[tex]v=3.88m/s[/tex]
Direction of the two players immediately after the tackle is North.
