In the accompanying diagram ab is tangent to circle O at B and ACD is a secant.
If AB=9 and AD=27, find AC

Answer:
AC = 3
Step-by-step explanation:
Based on tangent and secant theorem, thus:
AB² = AC × (AC + CD)
AB = 9
AD = AC + CD = 27
Plug in the values
9² = AC × (27)
81 = AC × 27
Divide both sides by 27
81/27 = AC
3 = AC
AC = 3