Answer :
Answer:
[tex]Rate = 15[/tex]
Step-by-step explanation:
Given
[tex]R(x) = 56 - 0.020x^2[/tex]
Required
Find the average change from 1,000 car seats to 1,050 car seats --- Missing information
This is calculated using:
[tex]Rate = \frac{R(b) - R(a)}{b-a}[/tex]
In this case:
[tex]a = 1000[/tex]
[tex]b = 1050[/tex]
Now, we have:
[tex]Rate = \frac{R(1050) - R(1000)}{1050-1000}[/tex]
[tex]Rate = \frac{R(1050) - R(1000)}{50}[/tex]
Calculating R(1050)
[tex]R(1050) = 56 *1050- 0.020*1050^2[/tex]
[tex]R(1050) = 58800-22050[/tex]
[tex]R(1050) = 36750[/tex]
Calculating R(1000)
[tex]R(1000) = 56 *1000- 0.020*1000^2[/tex]
[tex]R(1000) = 56000- 20000[/tex]
[tex]R(1000) = 36000[/tex]
So:
[tex]Rate = \frac{R(1050) - R(1000)}{50}[/tex]
[tex]Rate = \frac{750} {50}[/tex]
[tex]Rate = 15[/tex]
The average rate of change is 12