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GEOMETRY PROOFS ;-;
BRAINLIEST IF CORRECT!!

I'll report if you don't answer w something relevant to the problem (help me please..)

GIVEN: AE=BD; CD=CE
PROVE: AC=BC

GEOMETRY PROOFS ;-;BRAINLIEST IF CORRECT!!I'll report if you don't answer w something relevant to the problem (help me please..)GIVEN: AE=BD; CD=CEPROVE: AC=BC​ class=

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Answer:

1. ae=bd; cd=ce (given) 2. ae=ac+ce (segment addition postulate) 3. bd=ac+cd (substitution property of equality) 4. ac+cd=bd (symmetric property of equality) 5. bd=bc+cd (segment addition postulate) 6. ac+cd=bc+cd (transitive property of equality) 7. ac=bc (subtraction property of equality)

i think

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