Answer:
x intercept is 7 y intercept is -3
Step-by-step explanation:
Write equation out and have y=0
[tex] log_{2}(x - 1) - 3 = 0[/tex]
Add 3 to both sides
[tex] log_{2}(x - 1) = 3[/tex]
Using the log to exponet rule
[tex] (log_{b}(x) = y ) \: equal \: b {}^{y} = x[/tex]
Where b and x are real numbers and b cannot equal 1.
Reorder the equation as a exponet
[tex] log_{2}((x + 1) = 3[/tex]
[tex] {2}^{3} = x + 1[/tex]
Simplify
[tex]8 = x + 1[/tex]
Subtract 1 from both sides
[tex]x = 7[/tex]
So the x intercept is 7
To find y intercept plug 0 in as x
[tex] log_{2}(0 + 1) - 3 = y[/tex]
[tex] log_{2}(1) - 3 = y[/tex]
Add 3 to both sides
[tex] log_{2}(1) = y + 3[/tex]
Rewrite in exponet form
[tex] {2}^{y + 3} = 1[/tex]
Using the zero exponet property, anything to the zero power equal 1 so we must find a value that equal out to zero using the exponet so we'll set up the equation
[tex]y + 3 = 0[/tex]
Subtract 3 from both sides and we get
[tex]y = - 3[/tex]
So the x intercept is 7 and the y intercept is -3