Answer: Down Below
Step-by-step explanation: y=ab%5Ex
that goes through points (0, 10) and (2, 490)
y=ab%5Ex.......plug in (0, 10)
10=ab%5E0
10=a%2A1
a=10
so far
y=10b%5Ex......plug in (2, 490)
490=10b%5E2
b%5E2=490%2F10
b%5E2=49
b=sqrt%2849%29
b=7
your function is:+y=10%2A7%5Ex
A function assigns the values. The exponential function that goes through (0, 13) and (3, 832) is y=13(4)ˣ.
A function assigns the value of each element of one set to the other specific element of another set.
Given the exponential eqation is y=abˣ, substitute any one of the point in equation we will get,
13 = ab⁰
13 = a ₓ 1
a = 13
Therefore, the function can be written as y=13bˣ.
Substitute other point in the equation,
832 = 13 (b³)
b³ = 832/13
b³ = 64
b = 4
Hence, the exponential function that goes through (0, 13) and (3, 832) is y=13(4)ˣ.
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