Answer :
Answer:
The probability that at least 1 defective card is in the sample is [tex]0.9644[/tex]
Step-by-step explanation:
Here
N = 140
and n = 20
We will use the below given formula
P(at least 1 defective) = 1 - P( 0 defectives)
P( 0 defectives) =
[tex]= \frac{^{20}C_0 * ^{120}C_{20}}{ ^{140}C_{20}}\\= 0.0356 1-0.0356 \\= 0.9644[/tex]