PhotoMath isn’t helping please help

Answer:
Here,
a = 15. (Base)
b = 7. (Exponents power)
c = 4 (It's fourth root as denominator)
Step-by-step explanation:
As the form is
[tex] {\sqrt[4]{15}}^{7} = {15}^{ \frac{7}{4} } [/tex]
Answer:
a = 15, b = 7, c = 4
Step-by-step explanation:
Here's some facts that help with such tasks:
[tex](x^y)^z = x^{y\cdot z}\\\\\sqrt[y]{x} = x^{\frac{1}{y}}\\\\\sqrt[y]{x^z} = (x^z)^{\frac{1}{y}} = x^{\frac{z}{y}}\\\\\textrm{Using the last one we know:}\\\sqrt[4]{15^7} = 15^\frac{7}{4}\\\\\textrm{And bonus, not needed in this task:}\\x^y \cdot x^z = x^{y+z}[/tex]