Answer :

samuelpoly011

Answer:

cosec²x is the answer

Step-by-step explanation:

[tex]\frac{1+tan^2x}{tan^2x} \\\\\frac{sec^2x}{tan^2x} \\\\\frac{\frac{1}{cos^2x} }{\frac{sin^2x}{cos^2x} }\\\\\frac{1}{sin^2x}\\\\cosec^2x[/tex]

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