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Three resistors: R1 = 5 Ω,R2 = 3 Ω, and R3 = 4 Ω are connected in series to each other. A voltmeter connected in parallel to resistor R2 measures voltage of 6 V. What is the current through the battery?

Answer :

keijosalonen

Answer: current I= 2 A

Explanation: when resistors are in series current I is same

Through each resistor. Potential drop along resistor R is

ΔV= IR. then I = ΔV/R = 6V/3Ω

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