Answer :

lilyopal
(10+3i)(5-2i)
30i=50-20i
50i=50
i=1

maybe

Answer:

[tex]56-5i[/tex]

Step-by-step explanation:

Given are two complex numbers

10+3i and 5-2i

We are to find its product

Let us use foil method to multiply these two binomials.

[tex](10+3i)(5-2i)\\=50+15i-20i-6i^2\\[/tex]

Use the fact that i square =-1

We get product

= [tex]50-5i+6\\=56-5i[/tex]

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