Answer :
tanθ = √3 = √3 / 1
using a^2 + b^2 = c^2, the hypotenuse, the c = 2
So, draw this triangle, and you quickly notice that the angle is at π/3 radians or 60degrees and 4π/3 or 240degrees.
mathemaically...
tanθ = √3
tan^-1 √3 = θ
θ = π/3, 4π/3
or...in degrees,
θ = 60, 240
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
using a^2 + b^2 = c^2, the hypotenuse, the c = 2
So, draw this triangle, and you quickly notice that the angle is at π/3 radians or 60degrees and 4π/3 or 240degrees.
mathemaically...
tanθ = √3
tan^-1 √3 = θ
θ = π/3, 4π/3
or...in degrees,
θ = 60, 240
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!