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$6,000 dollars is invested in two different accounts earning 3% and 5% interest. At the end of one year, the two accounts earned $220 in interest. How much money was invested at 3%?

$2,000
$3,000
$4,000

Answer :

Answer:

$4000 is invested in the account which earning 3% rate .

Step-by-step explanation:

Formula

[tex]Simple\ interest = \frac{Principle\times Rate\times Time}{100}[/tex]

As given

$6,000 dollars is invested in two different accounts earning 3% and 5% interest.

At the end of one year, the two accounts earned $220 in interest.

Let us assume that the x amount is invested in the account which earning 3% interest .

Let us assume that the (6000 - x ) amount is invested in the account which earning 3% interest .

Thus the equation becomes

[tex]220 = \frac{x\times 3\times 1}{100} + \frac{(6000 - x)\times 5\times 1}{100}[/tex]

Simplfy the above equation

22000 = 3x + 30000 - 5x

30000 - 22000 = 5x - 3x

8000 = 2x

[tex]x = \frac{8000}{2}[/tex]

x = $4000

Therefore $4000 is invested in the account which earning 3% rate .

jtcolvert

Answer:

69420

Step-by-step explanation:

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