Answer:
5 units
Step-by-step explanation:
(4, -2 ) ; [tex]x_{1}=4[/tex] and [tex]y_{1} = -2[/tex]
(4 , 3) ; [tex]x_{2} = 4[/tex] and [tex]y_{2}=3[/tex]
distance = [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\[/tex]
[tex]= \sqrt{(4-4)^{2}+(3-[-2])^{2}}\\\\= \sqrt{0+(3+2)^{2}} \\\\=\sqrt{5^{2}}\\\\= 5 units[/tex]
