Answer :
Solution:
[tex]\text{mass of Pb = 1.15 × 10²⁴ Pb atoms} × \frac{\text{1 mol Pb}}{\text{6.022 × 10²³ Pb atoms}} × \frac{\text{207.2 g Pb}}{\text{1 mol Pb}}[/tex]
[tex]\boxed{\text{mass of Pb = 396 g}}[/tex]
[tex]\text{mass of Pb = 1.15 × 10²⁴ Pb atoms} × \frac{\text{1 mol Pb}}{\text{6.022 × 10²³ Pb atoms}} × \frac{\text{207.2 g Pb}}{\text{1 mol Pb}}[/tex]
[tex]\boxed{\text{mass of Pb = 396 g}}[/tex]