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A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100. You scored a 625. Calculate your z-score to the nearest hundredth (i.e. 2 decimal places).

z=

Answer :

JeanaShupp

Answer: The required z-score = 1.25

Step-by-step explanation:

Let x be a random variable that denotes the scores in the exam.

The formula for z-score = [tex]\dfrac{X-\text{mean}}{\text{standard deviation}}[/tex]

As per given, we have

X= 625, mean=500, standard deviation = 100

Z-score = [tex]\dfrac{625-500}{100}[/tex]

i.e. Z-score = [tex]\dfrac{125}{100}[/tex]

i.e. Z-score =1.25

Hence, the required z-score = 1.25

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