Find the measure of \angle G∠G. Round your answer to the nearest tenth (one decimal place).

Hi there!
[tex]\large\boxed{G \approx 55.44^{o}}[/tex]
To solve, we can use right triangle trigonometry.
Recall that:
sin = O/H, cos = A/H, tan = O/A.
For angle G, HF is its OPPOSITE side, and FG is the hypotenuse.
Therefore, we must use sine to evaluate:
sinG = 14 / 17
sin⁻¹ (14/17) = ∠G. Evaluate using a calculator.
∠G ≈ 55.44°