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Consider two circular swimming pools. Pool A has a radius of 24 feet, and Pool B has a diameter of 14.82 meters. Complete the description for which pool has a greater circumference. Round to the nearest hundredth for each circumference. 1 foot ≈ 0.305 meters The diameter of Pool A is meters. So, the diameter of Pool (select) is greater, and the circumference is (select) by meters.

Answer :

Pool A =
24 feet => 7.32 meters
circumference = 2 x pi x radius
circumference = 45.99 meters

Pool B =
circumference = pi x diameter
circumference = 46.56 meters

Therefore the diameter of Pool B is greater, and the circumference is 46.56 by meters.

Answer:

The diameter of Pool A is  14.64  meters. So, the diameter of Pool B  is greater, and the circumference is  greater  by  0.56 meters.

Step-by-step explanation:

Identify the diameter of Pool A.

d = 2r

d = 2(24) Substitute 24 for r.

d = 48 ft

Convert from feet to meters. Use the ratio of 1 foot to 0.305 meters. Round to the nearest hundredth.

48 × 0.305 = 14.64

The diameter of Pool A is about 14.64 meters.

Use the formula to find the circumference of Pool A.

C = πd

C = π(14.64) Substitute 14.64 for d.

C ≈ 3.14(14.64) Substitute 3.14 for π.

C ≈ 45.97 Multiply.

The circumference of Pool A is about 45.97 feet.

Identify the diameter of Pool B.

d = 14.82 m

The diameter of Pool B is 14.82 meters.

Use the formula to find the circumference of Pool B.

C = πd

C = π(14.82) Substitute 14.82 for d.

C ≈ 3.14(14.82) Substitute 3.14 for π.

C ≈ 46.53 Multiply.

The circumference of Pool B is about 46.53 feet.

The circumference of Pool B is greater than the circumference of Pool A.

Find how much greater the circumference of Pool B is compared to the circumference of Pool A.

46.53 − 45.97 = 0.56

The circumference of Pool B is greater than the circumference of Pool A by about 0.56 meters.

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